JEE MAIN - Physics (2021 - 18th March Morning Shift - No. 6)
The P-V diagram of a diatomic ideal gas system going under cyclic process as shown in figure. The work done during an adiabatic process CD is (use $$\gamma$$ = 1.4) :
_18th_March_Morning_Shift_en_6_1.png)
$$-$$500 J
$$-$$400 J
400 J
200 J
Explanation
Adiabatic process is from C to D
$$WD = {{{P_2}{V_2} - {P_1}{V_1}} \over {1 - \gamma }}$$
$$ = {{{P_D}{V_D} - {P_C}{V_C}} \over {1 - \gamma }}$$
$$ = {{200(3) - (100)(4)} \over {1 - 1.4}}$$
= $$-$$500 J
$$WD = {{{P_2}{V_2} - {P_1}{V_1}} \over {1 - \gamma }}$$
$$ = {{{P_D}{V_D} - {P_C}{V_C}} \over {1 - \gamma }}$$
$$ = {{200(3) - (100)(4)} \over {1 - 1.4}}$$
= $$-$$500 J
Comments (0)
