JEE MAIN - Physics (2021 - 18th March Morning Shift - No. 27)

What will be the average value of energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature T? (kB is Boltzmann constant)
$${1 \over 2}{k_B}T$$
$${2 \over 3}{k_B}T$$
$${3 \over 2}{k_B}T$$
$${k_B}T$$

Explanation

Energy associated with each digress of freedom is $${1 \over 2}{k_B}T$$.

Comments (0)

Advertisement