JEE MAIN - Physics (2021 - 18th March Morning Shift - No. 24)

A bullet of mass 0.1 kg is fired on a wooden block to pierce through it, but it stops after moving a distance of 50 cm into it. If the velocity of bullet before hitting the wood is 10 m/s and it slows down with uniform deceleration, then the magnitude of effective retarding force on the bullet is 'x' N. The value of 'x' to the nearest integer is __________.
Answer
10

Explanation

JEE Main 2021 (Online) 18th March Morning Shift Physics - Laws of Motion Question 79 English Explanation

Mbullet = 0.1 kg

V2 = 44 + 2($$-$$a) $$\times$$ 5

$$ \Rightarrow $$ 0 = (10)2 $$-$$ 2a $$\times$$ (0.5)

Retardation $$(a) = {{1000} \over {2 \times 5}}$$ = 100 m/s2

Retarding force (F) = ma = 0.1 $$\times$$ 100

FR = 10 N

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