JEE MAIN - Physics (2021 - 18th March Morning Shift - No. 24)
A bullet of mass 0.1 kg is fired on a wooden block to pierce through it, but it stops after moving a distance of 50 cm into it. If the velocity of bullet before hitting the wood is 10 m/s and it slows down with uniform deceleration, then the magnitude of effective retarding force on the bullet is 'x' N. The value of 'x' to the nearest integer is __________.
Answer
10
Explanation
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Mbullet = 0.1 kg
V2 = 44 + 2($$-$$a) $$\times$$ 5
$$ \Rightarrow $$ 0 = (10)2 $$-$$ 2a $$\times$$ (0.5)
Retardation $$(a) = {{1000} \over {2 \times 5}}$$ = 100 m/s2
Retarding force (F) = ma = 0.1 $$\times$$ 100
FR = 10 N
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