JEE MAIN - Physics (2021 - 18th March Morning Shift - No. 17)
The circuit shown in the figure consists of a charged capacitor of capacity 3 $$\mu$$F and a charge of $$\mu$$C. At time t = 0, when the key is closed, the value of current flowing through the 5 M$$\Omega$$ resistor is 'x' $$\mu$$-A. The value of 'x to the nearest integer is ___________.
_18th_March_Morning_Shift_en_17_1.png)
Answer
2
Explanation
_18th_March_Morning_Shift_en_17_2.png)
At time t
$$q = Q{e^{ - t/RC}}$$
$$I =$$ $${{dq} \over {dt}}$$ = $${Q \over {RC}}{e^{ - t/RC}}$$
at $$t = 0,I = {Q \over {RC}}{e^{ - 0/RC}}$$
$$I = {Q \over {RC}} = {{30} \over {5 \times {{10}^6} \times 3}} = 2 \times {10^{ - 6}}$$ A
$$ \Rightarrow $$ I = 2$$\mu$$A
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