JEE MAIN - Physics (2021 - 18th March Evening Shift - No. 19)

Consider a 72 cm long wire AB as shown in the figure. The galvanometer jockey is placed at P on AB at a distance x cm from A. The galvanometer shows zero deflection.

JEE Main 2021 (Online) 18th March Evening Shift Physics - Current Electricity Question 190 English
The value of x, to the nearest integer, is ___________.
Answer
48

Explanation

As galvanometer shows zero deflection so it act's as balanced wheatstone bridge.

$$ \therefore $$ $${{12} \over 6} = {x \over {72 - x}}$$

$$ \Rightarrow $$ 14 $$-$$ 2x = x

$$ \Rightarrow $$ 3x = 144

$$ \Rightarrow $$ x = 48 cm

Comments (0)

Advertisement