JEE MAIN - Physics (2021 - 17th March Morning Shift - No. 24)
Four identical rectangular plates with length, l = 2 cm and breadth, b = $${3 \over 2}$$ cm are arranged as shown in figure. The equivalent capacitance between A and C is $${{x{\varepsilon _0}} \over d}$$. The value of x is ______________. (Round off to the Nearest Integer)
_17th_March_Morning_Shift_en_24_1.png)
_17th_March_Morning_Shift_en_24_1.png)
Answer
2
Explanation
_17th_March_Morning_Shift_en_24_2.png)
$${C_{eq}} = {{2C \times C} \over {2C + C}} = {{2C} \over 3} $$
$$= {2 \over 3}{{{ \in _0}A} \over d} = {2 \over 3} \times {{{ \in _0}} \over d} \times \left( {2 \times {3 \over 2}} \right) = {{2{\varepsilon _0}} \over d}$$
Comments (0)
