JEE MAIN - Physics (2021 - 16th March Morning Shift - No. 28)
Consider a frame that is made up of two thin massless rods AB and AC as shown in the figure. A vertical force $$\overrightarrow P $$ of magnitude 100 N is applied at point A of the frame.
_16th_March_Morning_Shift_en_28_1.png)
Suppose the force is $$\overrightarrow P $$ resolved parallel to the arms AB and AC of the frame.
The magnitude of the resolved component along the arm AC is xN.
The value of x, to the nearest integer, is ___________.
[Given : sin(35$$^\circ$$) = 0.573, cos(35$$^\circ$$) = 0.819
sin(110$$^\circ$$) = 0.939, cos(110$$^\circ$$) = $$-$$ 0.342 J
Suppose the force is $$\overrightarrow P $$ resolved parallel to the arms AB and AC of the frame.
The magnitude of the resolved component along the arm AC is xN.
The value of x, to the nearest integer, is ___________.
[Given : sin(35$$^\circ$$) = 0.573, cos(35$$^\circ$$) = 0.819
sin(110$$^\circ$$) = 0.939, cos(110$$^\circ$$) = $$-$$ 0.342 J
Answer
82
Explanation
_16th_March_Morning_Shift_en_28_2.png)
Component along AC
= 100 cos 35$$^\circ$$ N
= 100 $$\times$$ 0.819 N
= 81.9 N
$$ \approx $$ 82 N
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