JEE MAIN - Physics (2021 - 16th March Morning Shift - No. 23)
The resistance R = $${V \over I}$$, where V = (50 $$\pm$$ 2)V and I = (20 $$\pm$$ 0.2)A. The percentage error in R is 'x'%. The value of 'x' to the nearest integer is _________.
Answer
5
Explanation
$$R = {V \over I}$$
$${{\Delta R} \over R} \times 100 = {{\Delta V} \over V} \times 100 + {{\Delta I} \over I} \times 100$$
% error in $$R = {2 \over {50}} \times 100 + {{0.2} \over {20}} \times 100$$
% error in R = 4 + 1
$$ \therefore $$ % error in R = 5%
$${{\Delta R} \over R} \times 100 = {{\Delta V} \over V} \times 100 + {{\Delta I} \over I} \times 100$$
% error in $$R = {2 \over {50}} \times 100 + {{0.2} \over {20}} \times 100$$
% error in R = 4 + 1
$$ \therefore $$ % error in R = 5%
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