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JEE MAIN - Physics (2021 - 16th March Morning Shift - No. 21)

In the figure given, the electric current flowing through the 5 k$$\Omega$$ resistor is 'x' mA.

JEE Main 2021 (Online) 16th March Morning Shift Physics - Current Electricity Question 199 English
The value of x to the nearest integer is ____________.
Answer
3

Explanation

JEE Main 2021 (Online) 16th March Morning Shift Physics - Current Electricity Question 199 English Explanation
$$I = {{21} \over {5 + 1 + 1}}$$

$$ \therefore $$ I = 3 mA

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