JEE MAIN - Physics (2021 - 16th March Morning Shift - No. 2)
The velocity-displacement graph describing the motion of bicycle is shown in the figure.
_16th_March_Morning_Shift_en_2_1.png)
The acceleration-displacement graph of the bicycle's motion is best described by :
The acceleration-displacement graph of the bicycle's motion is best described by :
_16th_March_Morning_Shift_en_2_2.png)
_16th_March_Morning_Shift_en_2_3.png)
_16th_March_Morning_Shift_en_2_4.png)
_16th_March_Morning_Shift_en_2_5.png)
Explanation
We know that, $$a = v{{dv} \over {dx}}$$
as slope is constant, so a $$\propto$$ v (from x = 0 to 200 m)
& slope = 0 so a = 0 (from x = 200 to 400 m)
$$ \therefore $$_16th_March_Morning_Shift_en_2_6.png)
as slope is constant, so a $$\propto$$ v (from x = 0 to 200 m)
& slope = 0 so a = 0 (from x = 200 to 400 m)
$$ \therefore $$
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