JEE MAIN - Physics (2021 - 16th March Morning Shift - No. 17)
A conducting bar of length L is free to slide on two parallel conducting rails as shown in the figure
_16th_March_Morning_Shift_en_17_1.png)
Two resistors R1 and R2 are connected across the ends of the rails. There is a uniform magnetic field $$\overrightarrow B $$ pointing into the page. An external agent pulls the bar to the left at a constant speed v.
The correct statement about the directions of induced currents I1 and I2 flowing through R1 and R2 respectively is :
_16th_March_Morning_Shift_en_17_1.png)
Two resistors R1 and R2 are connected across the ends of the rails. There is a uniform magnetic field $$\overrightarrow B $$ pointing into the page. An external agent pulls the bar to the left at a constant speed v.
The correct statement about the directions of induced currents I1 and I2 flowing through R1 and R2 respectively is :
Both I1 and I2 are in clockwise direction
I1 is in clockwise direction and I2 is in anticlockwise direction
I1 is in anticlockwise direction and I2 is in clockwise direction
Both I1 and I2 are in anticlockwise direction
Explanation
_16th_March_Morning_Shift_en_17_2.png)
When bar slides, area of loop 1 decreases and that of loop 2 increases. Magnetic flux decreases in 1 and increases in 2. Therefore induced emf and current resist this change. As a result B should increase in 1 and decrease in 2. So, I1 should be clockwise and I2 anticlockwise.
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