JEE MAIN - Physics (2020 - 9th January Morning Slot - No. 9)
Three harmonic waves having equal frequency
$$\nu $$ and same intensity $${I_0}$$, have phase angles 0, $${\pi \over 4}$$ and $$ - {\pi \over 4}$$ respectively. When they are
superimposed the intensity of the resultant wave
is close to :
5.8 I0
3 I0
0.2 I0
I0
Explanation
_9th_January_Morning_Slot_en_9_1.png)
I0 = CA2
AR = A + A$$\sqrt 2 $$ = A(1 + $$\sqrt 2 $$)
IR = C$$A_R^2$$
$$ \therefore $$ IR = CA2$${\left( {\sqrt 2 + 1} \right)^2}$$ = 5.8 I0
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