JEE MAIN - Physics (2020 - 9th January Evening Slot - No. 4)
The circuit shown below is working as a 8 V
dc regulated voltage source. When 12 V is used
as input, the power dissipated (in mW) in each
diode is; (considering both zener diodes are
identical) _________.
_9th_January_Evening_Slot_en_4_1.png)
Answer
40
Explanation
Current in circuit = $${{12 - 8} \over {200 + 200}}$$ = 10-2 A
So power dissipited in each diode = VI
= 4 $$ \times $$ 10-2
= 40 mW
So power dissipited in each diode = VI
= 4 $$ \times $$ 10-2
= 40 mW
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