JEE MAIN - Physics (2020 - 8th January Morning Slot - No. 9)
The graph which depicts the results of
Rutherford gold foil experiment with
$$\alpha $$-particales is :
$$\theta $$ : Scattering angle
Y : Number of scattered $$\alpha $$-particles detected (Plots are schematic and not to scale)
$$\theta $$ : Scattering angle
Y : Number of scattered $$\alpha $$-particles detected (Plots are schematic and not to scale)
_8th_January_Morning_Slot_en_9_1.png)
_8th_January_Morning_Slot_en_9_2.png)
_8th_January_Morning_Slot_en_9_3.png)
_8th_January_Morning_Slot_en_9_4.png)
Explanation
From Ernest Rutherford formula.
Which indicates that number of particles (Y)
that would be deflected by an angle ‘$$\theta $$’ due to
scattering is
$${Y_\theta } = {K \over {{{\sin }^4}{\theta \over 2}}}$$ where K = constant
Option (C) is the correct answer.
$${Y_\theta } = {K \over {{{\sin }^4}{\theta \over 2}}}$$ where K = constant
Option (C) is the correct answer.
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