JEE MAIN - Physics (2020 - 8th January Morning Slot - No. 3)
The coordinates of centre of mass of a uniform
flag shaped lamina (thin flat plate) of mass 4kg.
(The coordinates of the same are shown in
figure) are :
_8th_January_Morning_Slot_en_3_1.png)
(0.75m, 1.75m)
(1m, 1.75m)
(0.75m, 0.75m)
(1.25m, 1.50m)
Explanation
_8th_January_Morning_Slot_en_3_2.png)
m1 = $$\sigma $$A1 = $$\sigma $$$$ \times $$(1$$ \times $$2) = 2$$\sigma $$
m2 = $$\sigma $$A2 = $$\sigma $$$$ \times $$(2$$ \times $$1) = 2$$\sigma $$
$$ \therefore $$ xcm = $${{{m_1}{x_1} + {m_2}{x_2}} \over {{m_1} + {m_2}}}$$
= $${{2\sigma \times 0.5 + 2\sigma \times 1} \over {2\sigma + 2\sigma }}$$ = 0.75
and ycm = $${{{m_1}{y_1} + {m_2}{y_2}} \over {{m_1} + {m_2}}}$$
= $${{2\sigma \times 1 + 2\sigma \times 2.5} \over {2\sigma + 2\sigma }}$$ = 1.75
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