JEE MAIN - Physics (2020 - 8th January Morning Slot - No. 2)
The plot that depicts the behavior of the mean
free time t (time between two successive
collisions) for the molecules of an ideal gas, as
a function of temperature (T), qualitatively, is:
(Graphs are schematic and not drawn to scale)
(Graphs are schematic and not drawn to scale)
_8th_January_Morning_Slot_en_2_1.png)
_8th_January_Morning_Slot_en_2_2.png)
_8th_January_Morning_Slot_en_2_3.png)
_8th_January_Morning_Slot_en_2_4.png)
Explanation
Mean free time =
= $${{{1 \over {\sqrt 2 \pi {D^2}n}}} \over {\sqrt {{{8RT} \over {\pi M}}} }}$$
$$ \therefore $$ t $$ \propto $$ $${1 \over {\sqrt T }}$$
Mean free path
Average speed
= $${{{1 \over {\sqrt 2 \pi {D^2}n}}} \over {\sqrt {{{8RT} \over {\pi M}}} }}$$
$$ \therefore $$ t $$ \propto $$ $${1 \over {\sqrt T }}$$
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