JEE MAIN - Physics (2020 - 8th January Evening Slot - No. 17)
A plane electromagnetic wave of frequency
25 GHz is propagating in vacuum along the
z-direction. At a particular point in space and
time, the magnetic field is given by $$\overrightarrow B = 5 \times {10^{ - 8}}\widehat jT$$. The corresponding electric field $$\overrightarrow E $$ is (speed of light c = 3 × 108 ms–1)
15 $$\widehat i$$V / m
-15 $$\widehat i$$V / m
1.66 × 10–16 $$\widehat i$$V / m
-1.66 × 10–16 $$\widehat i$$V / m
Explanation
$$\overrightarrow E = \overrightarrow B \times \overrightarrow V $$
= $$\left( {5 \times {0^{ - 8}}\widehat j} \right) \times \left( {3 \times {{10}^8}\widehat k} \right)$$
= $${15\,\widehat i}$$ V/m
= $$\left( {5 \times {0^{ - 8}}\widehat j} \right) \times \left( {3 \times {{10}^8}\widehat k} \right)$$
= $${15\,\widehat i}$$ V/m
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