JEE MAIN - Physics (2020 - 7th January Morning Slot - No. 6)
The current I1 (in A) flowing through 1 $$\Omega $$ resistor in the following circuit is :
_7th_January_Morning_Slot_en_6_1.png)
_7th_January_Morning_Slot_en_6_1.png)
0.4
0.25
0.2
0.5
Explanation
Equivalent resistance of upper branch of circuit R = 2.5 $$\Omega $$
Voltage across upper branch = 1 V
$$ \therefore $$ i1 = $${1 \over {2.5}}$$ = 0.4 A
i = $${{0.4} \over 2}$$ = 0.2 A
_7th_January_Morning_Slot_en_6_2.png)
Voltage across upper branch = 1 V
$$ \therefore $$ i1 = $${1 \over {2.5}}$$ = 0.4 A
_7th_January_Morning_Slot_en_6_3.png)
i = $${{0.4} \over 2}$$ = 0.2 A
Comments (0)
