JEE MAIN - Physics (2020 - 7th January Morning Slot - No. 23)
Three point particles of masses 1.0 kg, 1.5 kg and 2.5 kg are placed at three corners of a right angle triangle of sides 4.0 cm, 3.0 cm and 5.0 cm as shown in the figure. The center of mass of the system is at a point:
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2.0 cm right and 0.9 cm above 1 kg mass
0.9 cm right and 2.0 cm above 1 kg mass
0.6 cm right and 2.0 cm above 1 kg mass
1.5 cm right and 1.2 cm above 1 kg mass
Explanation
_7th_January_Morning_Slot_en_23_2.png)
Let 1 kg as origin and x-y axis as shown
xcm = $${{1\left( 0 \right) + 1.5\left( 3 \right) + 2.5\left( 0 \right)} \over 5}$$ = 0.9 cm
ycm = $${{1\left( 0 \right) + 1.5\left( 0 \right) + 2.5\left( 4 \right)} \over 5}$$ = 2 cm
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