JEE MAIN - Physics (2020 - 6th September Morning Slot - No. 20)
A part of a complete circuit is shown in the figure. At some instant, the value of current I is 1A and
it is decreasing at a rate
of 102 A s–1. The value of the potential difference VP – VQ , (in volts) at that instant, is _________.
_6th_September_Morning_Slot_en_20_1.png)
of 102 A s–1. The value of the potential difference VP – VQ , (in volts) at that instant, is _________.
Answer
33
Explanation
VP + L.$${{di} \over {dt}}$$ - 30 + 2i = VQ
$$ \Rightarrow $$ VP + 50 $$ \times $$ 10-3(-102) - 30 + 2$$ \times $$1 = VQ
$$ \Rightarrow $$ VP - VQ = 35 - 2 = 33
_6th_September_Morning_Slot_en_20_2.png)
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