JEE MAIN - Physics (2020 - 4th September Morning Slot - No. 6)
A air bubble of radius 1 cm in water has an upward acceleration 9.8 cm s–2. The density of water is
1 gm cm–3 and water offers negligible drag force on the bubble. The mass of the bubble is (g = 980
cm/s2).
1.52 gm
4.51 gm
3.15 gm
4.15 gm
Explanation
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B - mg = ma
$$ \Rightarrow $$ m = $${B \over {g + a}}$$
= $${{V{\rho _w}g} \over {g + a}}$$
= $${{V{\rho _w}} \over {1 + {a \over g}}}$$
= $${{{4 \over 3}\pi {{\left( 1 \right)}^3} \times 1} \over {1 + {{9.8} \over {980}}}}$$
= 4.15 gm
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