JEE MAIN - Physics (2020 - 4th September Morning Slot - No. 19)
Two charged thin infinite plane sheets of
uniform surface charge density $${\sigma _ + }$$ and $${\sigma _ - }$$,
where |$${\sigma _ + }$$| > |$${\sigma _ - }$$|, intersect at right angle.
Which of the following best represents the
electric field lines for this system :
uniform surface charge density $${\sigma _ + }$$ and $${\sigma _ - }$$,
where |$${\sigma _ + }$$| > |$${\sigma _ - }$$|, intersect at right angle.
Which of the following best represents the
electric field lines for this system :
_4th_September_Morning_Slot_en_19_1.png)
_4th_September_Morning_Slot_en_19_2.png)
_4th_September_Morning_Slot_en_19_3.png)
_4th_September_Morning_Slot_en_19_4.png)
Explanation
_4th_September_Morning_Slot_en_19_5.png)
Given, |$${\sigma _ + }$$| > |$${\sigma _ - }$$|
We know, $$\left| {{E_ + }} \right| = {{\left| {{\sigma _ + }} \right|} \over {{\varepsilon _0}}}$$
and $$\left| {{E_ - }} \right| = {{\left| {{\sigma _ - }} \right|} \over {{\varepsilon _0}}}$$
$$ \therefore $$ $$\left| {{E_ + }} \right|$$ > $$\left| {{E_ - }} \right|$$
Thin infinite uniformly charged planes produces uniform electric field therefore option A and C are obviously wrong.
And as positive charge density is bigger in magnitude so its field along Y direction will be bigger than field of negative charge in X direction and this is evident in option B so it is correct.
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