JEE MAIN - Physics (2020 - 4th September Morning Slot - No. 17)
Take the breakdown voltage of the
zener diode used in the given circuit as 6V.
For the input voltage shown in figure below,
the time variation of the output voltage is:
(Graphs drawn are schematic and not to scale)_4th_September_Morning_Slot_en_17_1.png)
zener diode used in the given circuit as 6V.
For the input voltage shown in figure below,
the time variation of the output voltage is:
(Graphs drawn are schematic and not to scale)
_4th_September_Morning_Slot_en_17_2.png)
_4th_September_Morning_Slot_en_17_3.png)
_4th_September_Morning_Slot_en_17_4.png)
_4th_September_Morning_Slot_en_17_5.png)
Explanation
As there are two Zener diodes in reverse polarity so if one is in forward bias the other will be in reverse bias
and above 6V the reverse bias will too be in conduction mode. Therefore when voltage is more than 6V the
output will be constant. And when it is less than 6V it will follow the input voltage so correct answer is (C).
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