JEE MAIN - Physics (2020 - 4th September Evening Slot - No. 9)
The value of current i1
flowing from A to C in the circuit diagram is :
_4th_September_Evening_Slot_en_9_1.png)
1 A
4 A
5 A
2 A
Explanation
As this is act as Wheatstone bridge. So equivalent circuit becomes -
_4th_September_Evening_Slot_en_9_2.png)
$$ \therefore $$ I1 = $${8 \over {4 + 4}}$$ = 1 A
$$ \therefore $$ I1 = $${8 \over {4 + 4}}$$ = 1 A
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