JEE MAIN - Physics (2020 - 4th September Evening Slot - No. 4)
In a photoelectric effect experiment, the graph of stopping potential V versus reciprocal of wavelength
obtained is shown in the figure. As the intensity of incident radiation is increased :
_4th_September_Evening_Slot_en_4_1.png)
Slope of the straight line get more steep
Graph does not change
Straight line shifts to left
Straight line shifts to right
Explanation
eV = $${{hc} \over \lambda } - \phi $$
$$ \Rightarrow $$ V = $$\left( {{{hc} \over e}} \right){1 \over \lambda } - {\phi \over e}$$
Slope of the line in above equation and all other terms are independent of intensity. The graph does not change.
$$ \Rightarrow $$ V = $$\left( {{{hc} \over e}} \right){1 \over \lambda } - {\phi \over e}$$
Slope of the line in above equation and all other terms are independent of intensity. The graph does not change.
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