JEE MAIN - Physics (2020 - 4th September Evening Slot - No. 15)
Match the thermodynamic processes taking place in a system with the correct conditions. In the
table : $$\Delta $$Q is the heat supplied, $$\Delta $$W is the work done and $$\Delta $$U is change in internal energy of the
system.
| Process | Condition |
|---|---|
| (I) Adiabatic | (1) $$\Delta $$W = 0 |
| (II) Isothermal | (2) $$\Delta $$Q = 0 |
| (III) Isochoric | (3) $$\Delta $$U $$ \ne $$ 0, $$\Delta $$W $$ \ne $$ 0, $$\Delta $$Q $$ \ne $$ 0 |
| (IV) Isobaric | (4) $$\Delta $$U = 0 |
(I) - (1), (II) - (1), (III) - (2), (IV) - (3)
(I) - (2), (II) - (4), (III) - (1), (IV) - (3)
(I) - (1), (II) - (2), (III) - (4), (IV) - (4)
(I) - (2), (II) - (1), (III) - (4), (IV) - (3)
Explanation
(I) Adiabatic, $$\Delta $$Q = 0
(II) Isothermal, $$\Delta $$U = 0
(III) Isochoric, $$\int {pdV} $$ = 0 $$ \Rightarrow $$ W = 0
(IV) Isobaric process $$ \Rightarrow $$ Pressure remains constant
W = P.$$\Delta $$V $$ \ne $$ 0
$$\Delta $$U $$ \ne $$ 0
$$\Delta $$Q = nCp$$\Delta $$T $$ \ne $$ 0
(II) Isothermal, $$\Delta $$U = 0
(III) Isochoric, $$\int {pdV} $$ = 0 $$ \Rightarrow $$ W = 0
(IV) Isobaric process $$ \Rightarrow $$ Pressure remains constant
W = P.$$\Delta $$V $$ \ne $$ 0
$$\Delta $$U $$ \ne $$ 0
$$\Delta $$Q = nCp$$\Delta $$T $$ \ne $$ 0
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