JEE MAIN - Physics (2020 - 3rd September Morning Slot - No. 7)
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Consider a gas of triatomic molecules. The
molecules are assumed to be triangular and
made of massless rigid rods whose vertices
are occupied by atoms. The internal energy of
a mole of the gas at temperature T is :$${3 \over 2}RT$$
$${9 \over 2}RT$$
$${5 \over 2}RT$$
3RT
Explanation
Degree of freedom (f) = 3 + 3 = 6 and n = 1
U = $${f \over 2}nRT$$
= $${6 \over 2} \times 1 \times RT$$
= 3RT
U = $${f \over 2}nRT$$
= $${6 \over 2} \times 1 \times RT$$
= 3RT
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