JEE MAIN - Physics (2020 - 3rd September Morning Slot - No. 15)
In the circuit shown in the figure, the total charge is 750 $$\mu $$C and the voltage across capacitor C2
is
20 V. Then the charge on capacitor C2
is :
_3rd_September_Morning_Slot_en_15_1.png)
_3rd_September_Morning_Slot_en_15_1.png)
160 $$\mu $$C
450 $$\mu $$C
590 $$\mu $$C
650 $$\mu $$C
Explanation
_3rd_September_Morning_Slot_en_15_3.png)
Q2 = CV = 8 $$ \times $$ 20 = 160 $$\mu $$C
Q1 = 750 - 160 = 590 $$\mu $$C
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