JEE MAIN - Physics (2020 - 3rd September Morning Slot - No. 12)
When a diode is forward biased, it has a
voltage drop of 0.5 V. The safe limit of current
through the diode is 10 mA. If a battery of emf
1.5 V is used in the circuit, the value of
minimum resistance to be connected in series
with the diode so that the current does not
exceed the safe limit is
50 $$\Omega $$
200 $$\Omega $$
300 $$\Omega $$
100 $$\Omega $$
Explanation
_3rd_September_Morning_Slot_en_12_1.png)
1.5 ā 0.5 ā R $$ \times $$ 10ā2 = 0
$$ \Rightarrow $$ R = 100 $$\Omega $$
Comments (0)
