JEE MAIN - Physics (2019 - 9th January Morning Slot - No. 6)
A gas can be taken from A to B via two different processes ACB and ADB.
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When path ACB is used 60 J of heat flows into the system and 30 J of work is done by the system. If path ADB is used work done by the system is 10 J. The heat Flow into the system in path ADB is :
When path ACB is used 60 J of heat flows into the system and 30 J of work is done by the system. If path ADB is used work done by the system is 10 J. The heat Flow into the system in path ADB is :
40 J
80 J
100 J
20 J
Explanation
Using law of thermodynamics in path ACB,
$$\Delta $$QACB = $$\Delta $$UACB + $$\Delta $$WACB
$$ \Rightarrow $$ 60 = $$\Delta $$UACB + 30
$$ \Rightarrow $$ $$\Delta $$UACB = 30 J
As value of $$\Delta $$U is path independent,
$$ \therefore $$ $$\Delta $$UACB = $$\Delta $$UADB = 30 J
$$ \therefore $$ In path ADB,
$$\Delta $$QADB = $$\Delta $$UADB + $$\Delta $$WADB
$$ \Rightarrow $$$$\Delta $$QADB = 30 + 10 = 40 J
$$\Delta $$QACB = $$\Delta $$UACB + $$\Delta $$WACB
$$ \Rightarrow $$ 60 = $$\Delta $$UACB + 30
$$ \Rightarrow $$ $$\Delta $$UACB = 30 J
As value of $$\Delta $$U is path independent,
$$ \therefore $$ $$\Delta $$UACB = $$\Delta $$UADB = 30 J
$$ \therefore $$ In path ADB,
$$\Delta $$QADB = $$\Delta $$UADB + $$\Delta $$WADB
$$ \Rightarrow $$$$\Delta $$QADB = 30 + 10 = 40 J
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