JEE MAIN - Physics (2019 - 9th January Evening Slot - No. 4)
Ge and Si diodes start conducting at 0.3 V and 0.7 V respectively. In the following figure if Ge diode connection are reversed, the value of V0 changes by : (assume that the Ge diode has large breakdown voltage)
_9th_January_Evening_Slot_en_4_1.png)
0.8 V
0.6 V
0.2 V
0.4 V
Explanation
Case 1 :
_9th_January_Evening_Slot_en_4_2.png)
Ge need 0.3 V for start conducting and Si need 0.7 V for start conducting.
So, conduction will be start by Ge.
Out of 12 V, 0.3V will be consumed by Ge.
$$ \therefore $$ V01 = 12 $$-$$ 0.3 = 11.7 V
Case 2 :
_9th_January_Evening_Slot_en_4_3.png)
Here as Ge diode is in reverse bias so no conduction will happen through Ge diode
As Si diode is in forward bias so conduction will happen through Si diode.
Here Si diode consume 0.7 V.
So, V02 = 12 $$-$$ 0.7 = 11.3 V
$$ \therefore $$ Value of V0 changes by
= 11.7 $$-$$ 11.3 = 0.4 V
Ge need 0.3 V for start conducting and Si need 0.7 V for start conducting.
So, conduction will be start by Ge.
Out of 12 V, 0.3V will be consumed by Ge.
$$ \therefore $$ V01 = 12 $$-$$ 0.3 = 11.7 V
Case 2 :
Here as Ge diode is in reverse bias so no conduction will happen through Ge diode
As Si diode is in forward bias so conduction will happen through Si diode.
Here Si diode consume 0.7 V.
So, V02 = 12 $$-$$ 0.7 = 11.3 V
$$ \therefore $$ Value of V0 changes by
= 11.7 $$-$$ 11.3 = 0.4 V
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