JEE MAIN - Physics (2019 - 9th April Morning Slot - No. 14)
A ball is thrown vertically up (taken as +z-axis)
from the ground. The correct momentum-height
(p-h) diagram is :
_9th_April_Morning_Slot_en_14_1.png)
_9th_April_Morning_Slot_en_14_2.png)
_9th_April_Morning_Slot_en_14_3.png)
_9th_April_Morning_Slot_en_14_4.png)
Explanation
Momentum p = mv …(1)
and for motion under gravity $$h = {{{u^2} - {v^2}} \over {2g}}$$ ...(2)
$$h = {{{u^2} - {p^2}/m} \over {2g}}$$
and for motion under gravity $$h = {{{u^2} - {v^2}} \over {2g}}$$ ...(2)
$$h = {{{u^2} - {p^2}/m} \over {2g}}$$
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