JEE MAIN - Physics (2019 - 9th April Evening Slot - No. 4)
The parallel combination of two air filled
parallel plate capacitors of capacitance C and
nC is connected to a battery of voltage, V. When
the capacitors are fully charged, the battery is
removed and after that a dielectric material of
dielectric constant K is placed between the two
plates of the first capacitor. The new potential
difference of the combined system is :-
V
$${V \over {K + n}}$$
$${{(n+1)V} \over {K + n}}$$
$${{nV} \over {K + n}}$$
Explanation
_9th_April_Evening_Slot_en_4_1.png)
Initially Q = CV(1 + n)$$ \therefore $$ Ceq = (K + n)C
$$ \therefore $$ $$V = {{CV\left( {1 + n} \right)} \over {\left( {K + n} \right)C}} = {{V\left( {1 + n} \right)} \over {\left( {K + n} \right)}}$$
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