JEE MAIN - Physics (2019 - 9th April Evening Slot - No. 28)
Two coils 'P' and 'Q' are separated by some
distance. When a current of 3 A flows through
coil 'P', a magnetic flux of 10–3 Wb passes
through 'Q'. No current is passed through 'Q'.
When no current passes through 'P' and a
current of 2 A passes through 'Q', the flux
through 'P' is :-
3.67 × 10–4 Wb
3.67 × 10–3 Wb
6.67 × 10–4 Wb
6.67 × 10–3 Wb
Explanation
Mutual induction
$${\phi _q} = M{I_p}$$
10–3 = M(3)
$$ \Rightarrow M = {1 \over 3} \times {10^{ - 3}}$$
$${\phi _p} = M{I_q}$$
$$ \Rightarrow {\phi _p} = 6.67{\rm{ }} \times {\rm{ }}{10^{-4}}{\rm{ }}Wb$$
$${\phi _q} = M{I_p}$$
10–3 = M(3)
$$ \Rightarrow M = {1 \over 3} \times {10^{ - 3}}$$
$${\phi _p} = M{I_q}$$
$$ \Rightarrow {\phi _p} = 6.67{\rm{ }} \times {\rm{ }}{10^{-4}}{\rm{ }}Wb$$
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