JEE MAIN - Physics (2019 - 8th April Evening Slot - No. 26)
Calculate the limit of resolution of a telescope
objective having a diameter of 200 cm, if it has
to detect light of wavelength 500 nm coming
from a star :-
610 × 10–9 radian
457.5 × 10–9 radian
305 × 10–9 radian
152.5 × 10–9 radian
Explanation
Limit of resolution of telescope $$(\theta) = {{1.22\lambda } \over D}$$
$$\theta = {{1.22 \times 500 \times {{10}^{ - 9}}} \over {200 \times {{10}^{ - 2}}}} = {{1.22 \times 500 \times {{10}^{ - 9}}} \over 2}$$
$$\theta $$ = 305 × 10–9 radian
$$\theta = {{1.22 \times 500 \times {{10}^{ - 9}}} \over {200 \times {{10}^{ - 2}}}} = {{1.22 \times 500 \times {{10}^{ - 9}}} \over 2}$$
$$\theta $$ = 305 × 10–9 radian
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