JEE MAIN - Physics (2019 - 8th April Evening Slot - No. 12)
In the figure shown, what is the current
(in Ampere) drawn from the battery ?
You are given: R1 = 15$$\Omega $$, R2 = 10 $$\Omega $$, R3 = 20 $$\Omega $$, R4 = 5$$\Omega $$, R5 = 25$$\Omega $$, R6 = 30 $$\Omega $$, E = 15 V_8th_April_Evening_Slot_en_12_1.png)
You are given: R1 = 15$$\Omega $$, R2 = 10 $$\Omega $$, R3 = 20 $$\Omega $$, R4 = 5$$\Omega $$, R5 = 25$$\Omega $$, R6 = 30 $$\Omega $$, E = 15 V
13/24
7/18
9/32
20/3
Explanation
Equivalent resistance of the given circuit
$${R_{eq}} = 45 + {{10 \times 50} \over {10 + 50}} = \left( {45 + {{50} \over 6}} \right)\Omega $$
$$ \Rightarrow $$ $${{160} \over 3}\Omega $$
$$ \therefore $$ $$I = {{15} \over {{{160} \over 3}}} = {9 \over {32}}A$$
$${R_{eq}} = 45 + {{10 \times 50} \over {10 + 50}} = \left( {45 + {{50} \over 6}} \right)\Omega $$
$$ \Rightarrow $$ $${{160} \over 3}\Omega $$
$$ \therefore $$ $$I = {{15} \over {{{160} \over 3}}} = {9 \over {32}}A$$
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