JEE MAIN - Physics (2019 - 12th January Evening Slot - No. 6)
A 10 m long horizontal wire extends from North East to South West. It is falling with a speed of 5.0 ms–1, at right angles to the horizontal component of the earth's magnetic field of 0.3 $$ \times $$ 10–4 Wb/m2. The value of the induced emf in wire is :
0.3 $$ \times $$ 10–3 V
2.5 $$ \times $$ 10–3 V
1.5 $$ \times $$ 10–3 V
1.1 $$ \times $$ 10–3 V
Explanation
Induied emf = Bv$$\ell $$ sin 45o
= 0.3 $$ \times $$ 10$$-$$4 $$ \times $$ 5 $$ \times $$ 10 $$ \times $$ sin 45o
= 1.1 $$ \times $$ 10$$-$$3 V
= 0.3 $$ \times $$ 10$$-$$4 $$ \times $$ 5 $$ \times $$ 10 $$ \times $$ sin 45o
= 1.1 $$ \times $$ 10$$-$$3 V
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