JEE MAIN - Physics (2019 - 12th January Evening Slot - No. 21)
A galvanometer, whose resistance is 50 ohm, has 25 divisions in it. When a current of 4 $$ \times $$ 10–4 A passes through it, its needle ( pointer) deflects by one division. To use this galvanometer as a voltmeter of range 2.5 V, it should be connected to a resistance of :
200 ohm
250 ohm
6200 ohm
6250 ohm
Explanation
Ig = 4 $$ \times $$ 10$$-$$4 $$ \times $$ 25 = 10$$-$$2 A
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2.5 = (50 + R) 10$$-$$2
$$ \therefore $$ R = 200 $$\Omega $$
2.5 = (50 + R) 10$$-$$2
$$ \therefore $$ R = 200 $$\Omega $$
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