JEE MAIN - Physics (2019 - 12th January Evening Slot - No. 15)
In the given circuit diagram, the currents, I1 = – 0.3 A, I4 = 0.8 A and I5 = 0.4 A, are flowing as shown. The currents I2, I3 and I6, respectively, are :
_12th_January_Evening_Slot_en_15_1.png)
1.1 A, – 0.4 A, 0.4 A
$$-$$ 0.4 A, 0.4 A, 1.1 A
0.4 A, 1.1 A, 0.4 A
1.1 A, 0.4 A, 0.4 A
Explanation
_12th_January_Evening_Slot_en_15_2.png)
From KCL, I3 = 0.8 $$-$$ 0.4 = 0.4A
I2 = 0.4 + 0.4 + 0.3
= 1.1 A
I6 = 0.4A
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