JEE MAIN - Physics (2019 - 12th April Morning Slot - No. 26)

A man (mass = 50 kg) and his son (mass = 20 kg) are standing on a frictionless surface facing each other. The man pushes his son so that he starts moving at a speed of 0.70 ms–1 with respect to the man. The speed of the man with respect to the surface is :
0.28 ms–1
0.47 ms–1
0.20 ms–1
0.14 ms–1

Explanation

50 V1 = 20 V2

V1 + V2 = 0.70

V1 = 0.20

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