JEE MAIN - Physics (2019 - 11th January Morning Slot - No. 24)
A hydrogen atom, initially in the ground state is excited by absorbing a photon of wavelength 980$$\mathop A\limits^ \circ $$. The radius of the atom in the excited state, in terms of Bohr radius a0 will be : (hc = 12500 eV$$\mathop A\limits^ \circ $$)
4a0
9a0
25a0
16a0
Explanation
Energy of photon $$ = {{12500} \over {980}} = 12.75eV$$
$$ \therefore $$ Electron will excite to n = 4
Since 'R' $$ \propto $$ n2
$$ \therefore $$ Radius of atom will be 16a0
$$ \therefore $$ Electron will excite to n = 4
Since 'R' $$ \propto $$ n2
$$ \therefore $$ Radius of atom will be 16a0
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