JEE MAIN - Physics (2019 - 11th January Evening Slot - No. 21)
A monochromatic light is incident at a certain angle on an equilateral triangular prism and suffers minimum deviation. If the refractive index of the material of the prism is $$\sqrt 3 $$, then the angle of incidence is:
60o
45o
90o
30o
Explanation
i = e
r1 = r2 = $${A \over 2}$$ = 30o
by Snell's law
1 $$ \times $$ sin i = $$\sqrt 3 \times {1 \over 2} = {{\sqrt 3 } \over 2}$$
i = 60
r1 = r2 = $${A \over 2}$$ = 30o
by Snell's law
1 $$ \times $$ sin i = $$\sqrt 3 \times {1 \over 2} = {{\sqrt 3 } \over 2}$$
i = 60
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