JEE MAIN - Physics (2019 - 10th January Morning Slot - No. 5)
A homogeneous solid cylindrical roller of radius R and mass M is pulled on a cricket pitch by a horizontal force. Assuming rolling without slipping, angular acceleration of the cylinder is -
$${F \over {2mR}}$$
$${2F \over {3mR}}$$
$${3F \over {2mR}}$$
$${F \over {3mR}}$$
Explanation
_10th_January_Morning_Slot_en_5_1.png)
FR = $${3 \over 2}$$ MR2$$\alpha $$
$$\alpha $$ = $${{2F} \over {3MR}}$$
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