JEE MAIN - Physics (2019 - 10th January Morning Slot - No. 4)
A 2 W carbon resistor is color coded with green, black, red and brown respectively. The maximum current which can be passed through this resistor is -
0.4 mA
20 mA
63 mA
100 mA
Explanation
P = i2R.
$$ \therefore $$ for imax, R must be minimum
from color coding R = 50 $$ \times $$ 102$$\Omega $$
$$ \therefore $$ imax = 20mA
$$ \therefore $$ for imax, R must be minimum
from color coding R = 50 $$ \times $$ 102$$\Omega $$
$$ \therefore $$ imax = 20mA
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