JEE MAIN - Physics (2019 - 10th January Morning Slot - No. 14)

Water flows into a large tank with flat bottom at the rate of 10^–4m³s^–1. Water is also leaking out of a hole ofarea 1 cm² at its bottom. If the height of the water in the tank remains steady, then this height is -

2.9 cm

5.1 cm

4 cm

1.7 cm

Explanation

Since height of water column is constant therefore, water inflow rate (Q_in)

= water outflow rate

Q_in = 10^$$-$$4 m³s^$$-$$1

Q_out = Au = 10^$$-$$4 $$ \times $$ $$\sqrt {2gh} $$

10^$$-$$4 = 10^$$-$$4 $$\sqrt {20 \times h} $$

h = $${1 \over {20}}m$$

h = 5cm

JEE MAIN - Physics (2019 - 10th January Morning Slot - No. 14)

Explanation

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