JEE MAIN - Physics (2019 - 10th January Evening Slot - No. 17)

Half mole of an ideal monoatomic gas is heated at constant pressure of 1 atm from 20oC to 90oC. Work done by gas is close to – (Gas constant R = 8.31 J/mol.K)
581 J
73 J
146 J
291 J

Explanation

WD = P$$\Delta $$V = nR$$\Delta $$T = $${1 \over 2} \times 8.31 \times 70$$

Comments (0)

Advertisement