JEE MAIN - Physics (2019 - 10th January Evening Slot - No. 16)
Two kg of a monoatomic gas is at a pressure of 4 $$ \times $$ 104 N/m2. The density of the gas is 8 kg/m3. What is the order of energy of the gas due to its thermal motion ?
104 J
103 J
105 J
106 J
Explanation
Thermal energy of N molecule
= N$$\left( {{3 \over 2}kT} \right)$$
= $${N \over {{N_A}}}{3 \over 2}$$RT
= $${3 \over 2}$$(nRT)
= $${3 \over 2}$$PV
= $${3 \over 2}$$P$$\left( {{m \over 8}} \right)$$
= $${3 \over 2}$$ $$ \times $$ 4 $$ \times $$ 104 $$ \times $$ $${2 \over 8}$$
= 1.5 $$ \times $$ 104
order will 104
= N$$\left( {{3 \over 2}kT} \right)$$
= $${N \over {{N_A}}}{3 \over 2}$$RT
= $${3 \over 2}$$(nRT)
= $${3 \over 2}$$PV
= $${3 \over 2}$$P$$\left( {{m \over 8}} \right)$$
= $${3 \over 2}$$ $$ \times $$ 4 $$ \times $$ 104 $$ \times $$ $${2 \over 8}$$
= 1.5 $$ \times $$ 104
order will 104
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