JEE MAIN - Physics (2019 - 10th January Evening Slot - No. 11)
The eye can be regarded as a single refracting surface. The radius of curvature of this surface is equal to that of cornea (7.8 mm). This surface separateds two media of refractive indices 1 and 1.34. Calculate the distance from the refracting surface at which a parallel beam of light will come to focus -
2 cm
3.1 cm
4.0 cm
1 cm
Explanation
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$${{1.34} \over V} - {1 \over \infty } = {{1.34 - 1} \over {7.8}}$$
$$ \therefore $$ V = 30.7 mm
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