JEE MAIN - Physics (2019 - 10th January Evening Slot - No. 10)
An unknown metal of mass 192 g heated to a temperature of 100oC was immersed into a brass calorimeter of mass 128 g containing 240 g of water at a temperature of 8.4oC. Calculate the specific heat of the unknown metal if water temperature stabilizes at 21.5oC. (Specific heat of brass is 394 J kg–1 K–1)
458 J kg–1 K–1
1232 J kg–1 K–1
654 J kg–1 K–1
916 J kg–1 K–1
Explanation
192 $$ \times $$ S $$ \times $$ (100 $$-$$ 21.5)
= 128 $$ \times $$ 394 $$ \times $$ (21.5 $$-$$ 8.4)
+ 240 $$ \times $$ 4200 $$ \times $$ (21.5 $$-$$ 8.4)
$$ \Rightarrow $$ S = 916
= 128 $$ \times $$ 394 $$ \times $$ (21.5 $$-$$ 8.4)
+ 240 $$ \times $$ 4200 $$ \times $$ (21.5 $$-$$ 8.4)
$$ \Rightarrow $$ S = 916
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