JEE MAIN - Physics (2019 - 10th April Morning Slot - No. 5)
A transformer consisting of 300 turns in the
primary and 150 turns in the secondary gives
output power of 2.2 kW. If the current in the
secondary coil is 10A, then the input voltage
and current in the primary coil are :
220 V and 20 A
220 V and 10A
440 V and 5A
440 V and 20 A
Explanation
Given NP = 300, Ns = 150, P0 = 2200W
Is = 10 A
P0 = V0I0 $$ \Rightarrow $$ 2200 = V0 × 10 $$ \Rightarrow $$ V0 = 220 V
$$ \because $$ $${{{V_i}} \over {{V_0}}} = {{{N_P}} \over {{N_S}}} \Rightarrow {V_i} = 2 \times 220 = 440\,V$$
Also, P0 = ViIi
$$ \Rightarrow {I_i} = {{2200} \over {440}} = 5A$$
Is = 10 A
P0 = V0I0 $$ \Rightarrow $$ 2200 = V0 × 10 $$ \Rightarrow $$ V0 = 220 V
$$ \because $$ $${{{V_i}} \over {{V_0}}} = {{{N_P}} \over {{N_S}}} \Rightarrow {V_i} = 2 \times 220 = 440\,V$$
Also, P0 = ViIi
$$ \Rightarrow {I_i} = {{2200} \over {440}} = 5A$$
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